1.

At a particular temperature, the ratio of molar conductance to specific conductance of 0.01 M NaCl solution is

Answer»

`10^5 cm^3 MOL^(-1)`
`10^3 cm^3 mol^(-1)`
`10 cm^3 mol^(-1)`
`10^5 cm^2 mol^(-1)`

Solution :`^^_m` (molar conductance)`=(kxx1000)/M`
`(^^_m(OHM^(-1)cm^2mol^(-1)))/(K(ohm^(-1)cm^(-1)))=1000/M=1000/(0.01)cm^3mol^(-1)`
`=10^5cm^3mol^(-1)`


Discussion

No Comment Found

Related InterviewSolutions