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At a particular temperature, PCl_(5)(g)undergoes 50% dissociation. The equilibrium constant for PCl_(5)(g) rarr PCl_(3)(g) + Cl_(2)(g) is 2atm. The pressure of the equilibrium mixture is |
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Answer» Solution :`PCl_(5) RARR PCl_(3)+ Cl_(2)` `K_(p) = (0.5/1.5)p(0.5/1.5)p/(0.5/1.5)p implies k_(p) = (0.5/1.5)p` `2 = p/3 implies p = 2 xx 3 = 6 atm` |
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