1.

At a given temperaturee, the equilibrium constant for reaction PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))is 2.4xx10^(-3). At the same temperaturee, the equlibrium constant for reaction PCl_(3(g))+Cl_(2(g))hArrPCl_(5(g))is

Answer»

`2.4xx10^(-3)`
`-2.4xx10^(-3)`
`-4.2xx10^(2)`
`4.8xx10^(-2)`

Solution :REACTION is reversed. HENCE
`K=(1)/((2.4xx10^(3)))=4.2xx10^(2)`


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