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At a given temperature, the vapour pressure in mm of Hg of a solution of two volatile liquids A and B is given by the equation p=120-80X_(B)(X_(B)="mole fraction of B") Calculate the vapour pressures of pure A and B at the same temperature. |
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Answer» Solution :When `X_(B)=0`, we have pure A`""therefore""p_(A)^(@)=120-80xx0=120mm` The given EXPRESSION can be written as `""p=120-80(1-X_(A))` When `X_(A)=0`, we have pure B`""therefore""p_(B)^(@)=120-80(1-0)=40mm` Alternatively, for pure B, `x_(B)=1`. HENCE, `p_(B)^(@)=120-80xx1=40mm` |
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