1.

At a given temperature, the reaction A(g)+2B(g)toC(g) , is at equilibrium. At the start of the reaction, p_A = 0.25 atm and p_B = 0.5 atm. When the reaction reaches equilibrium, 50 % of C(g) is found to have formed. Calculate the K_P for the reaction. What initial pressure should B(g) have for the production of 75% C(g)?

Answer»

SOLUTION :`A(g)+2B(g) partial pressure `0.25-0.25xx(50)/(100)0.5-0.5xx(50)/(100)0.25xx(50)/(100)`
at EQUILIBRIUM: =0.125atm=0.25atm=0.25atm
`K_p=(p_C)/(P_Axxp_B^2)=(0.125)/(0.125xx(0.25)^2)=16`
Let, for 75% YIELD of C(g), the initial pressure of
B(g)=p atm
`A(g)+2B(g) Equilibrium: `0.25-0.25xx(75)/(100)p-2xx0.25xx(75)/(100)0.25xx(75)/(100)`
`=0.0625atm""=p-0.375""=0.1875`
`K_p=(p_c)/(p_Axxp_B^2)=16`
or `(0.1875)/(0.0625xx(p-0.375)^2)=16" ":.p=0.808atm`


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