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At a given temperature, the reaction A(g)+2B(g)toC(g) , is at equilibrium. At the start of the reaction, p_A = 0.25 atm and p_B = 0.5 atm. When the reaction reaches equilibrium, 50 % of C(g) is found to have formed. Calculate the K_P for the reaction. What initial pressure should B(g) have for the production of 75% C(g)? |
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Answer» SOLUTION :`A(g)+2B(g) at EQUILIBRIUM: =0.125atm=0.25atm=0.25atm `K_p=(p_C)/(P_Axxp_B^2)=(0.125)/(0.125xx(0.25)^2)=16` Let, for 75% YIELD of C(g), the initial pressure of B(g)=p atm `A(g)+2B(g) `=0.0625atm""=p-0.375""=0.1875` `K_p=(p_c)/(p_Axxp_B^2)=16` or `(0.1875)/(0.0625xx(p-0.375)^2)=16" ":.p=0.808atm` |
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