1.

At a given temperature, NH_3 gas is in a state of equilibrium with N_2 and H_2 gases in a closed container. If the partial pressures of N_2 and H_2 in the mixture are 1.34 and 0.67 atm respectively and the total pressure of the reaction mixture is 4.67 atm, then determine the value of K_p for the reaction : N_2(g)+3H_2(g)

Answer»

SOLUTION :TOTAL pressure of the mixture = 4.67 ATM. In the mixture,
`p_(N_2)=1.34atm,p_(H_2)=0.67atm`
`pNH_3=[4.67-(1.34+0.67)]=2.66atm`

`N_2+3H_2 `K_p=(p_(NH_3)^2)/(p_(N_2)xxp_(H_2)^3)=((2.66)^2)/(1.34xx(0.67)^3)=17.56atm^(-2)`


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