Saved Bookmarks
| 1. |
At a distance of `5 cm and 10 cm` outward from the surface of a uniformly charged solid sphere, the potentials are `100 V and 75 V`, repectively. Then.A. potential at its surface is `150 V`B. the charge on the sphere is `(5//3)xx10^(-10)C`C. the electric field on the surface is `1500 V//m`D. the electric potential at its centre is `225 V` |
|
Answer» Correct Answer - A::C::D Potential at 5 cm from surface`=(KQ)/(R+5)=100` Potential at `10` cm from surface `=(KQ)/(R+10)=75 rArr R=10` cm. `:.` Potential at surface `=(KQ)/(R)=(100xx15)/10=150 V` Electric field on surface`=(KQ)/R^(2)=(100xx15Vxxcm)/(100 cm^(2))` `=1500 V//m` |
|