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At a distance L=400m away from the signal light, brakes are applied to a locomotive moving with a velocity, u=54km/h. determine the position of rest of the locomotive relative to the signal light after 1 min of the application of the brakes if its acceleration a= -0.3 m/s2 ?? |
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Answer» Correct option isC17.69ms −1 Total distance COVERED(s) = Distance during ACCELERATION(s 1 ) + distance during uniform motion(s 2 ) + distance during RETARDATION(s 3 )For acceleration,v=u+a∗tv max =2×10=20 m/ss=ut+(1/2)at 2 s 1 =(1/2)×2×10 2 =100 mFor uniform motion,s=vts 2 =20×200 =4000 mDuring retardation,v=u+at0=20+50t =−0.4 m/s 2 s 3 =ut+(1/2)at 2 =20×50+(1/2)×(−0.4)×50 2 =500 mTotal distance travelled, s=s1+s2+s3=100+4000+500=4600 mTotal time TAKEN, t=t 1 +t 2 +t 3 =260 sAverage velocity, v avg = Total TimeTotal Distance =4600/260=17.69 m/s |
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