At a depth of 5 m below the free surface of a liquid, an air bubble of radius 2 mm is formed. The pressure inside the bubble will be (The surface tension of water is 20 xx 10^(-8)" N/m.")

At a depth of 5 m below the free surface of a liquid, an air bubble of

1.	At a depth of 5 m below the free surface of a liquid, an air bubble of radius 2 mm is formed. The pressure inside the bubble will be (The surface tension of water is 20 xx 10^(-8)" N/m.")
Answer» <P>`2 xx 10^(5) N//m^(2)` `1.5 xx 10^(5) N//m^(2)` `3 xx 10^(5) N//m^(2)` `5 xx 10^(5) N//m^(2)` Solution :Pressure inside the BUBBLE `=(P_(o)+PGH)+(2T)/(r)` `=(10^(5)+10^(3)+10 xx 5)+2 xx (20 xx 10^(-8))/(2 xx 10^(-3))` `=150000 +20 xx 10^(-5)` `=1.5 xx 10^(5)N//m^(2))`