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At a constant pressure of `10^(4)Nm^(-2)` , a gas expands by `0.25m^(3)` work done by the gas isA. 2500 JB. 250 J/kg KC. 25 JD. 2.5 J |
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Answer» Correct Answer - A `W=PdV` `=10^(4)xx0.25` =2500 J. |
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