1.

At a constant pressure of `10^(4)Nm^(-2)` , a gas expands by `0.25m^(3)` work done by the gas isA. 2500 JB. 250 J/kg KC. 25 JD. 2.5 J

Answer» Correct Answer - A
`W=PdV`
`=10^(4)xx0.25`
=2500 J.


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