1.

At a certain temperature the time required for the complete diffusion of 200 mL of H_(2) gas is 30 minutes. The time required for the complete diffusion of 50 mL of O_(2) gas at the same temperature will be

Answer»

60 minutes
30 minutes
45 minutes
15 minutes.

Solution :According to Graham.s law of DIFFUSION or effusion.
Rate of diffusion of a gas (R)
`=("Volume of the gas diffused"(V))/("Time taken for the diffusion"(t))`
Now according to Graham.s law.
`r prop 1/(SQRT("Molecular mass of the gas"))` i.e. `r prop 1/(sqrt(M))`
Now `(r_(H_(2)))/(r_(O_(2)))sqrt((M_(O_(2)))/(M_(H_(2))))implies(200//30)/(50//t)=sqrt(32/2)`
Where t is the time taken for diffusion of 50 mL of `O_(2)` gas.
`implies200/30xx5/50=4impliest=30` min


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