At a certain temperature, the half life period for the catalytic decomposition of ammonia were found to be a follows. Pressure (mm): 100 200 Half life (min.) : 1.92 1.0 What is the unit of rate constant?

At a certain temperature, the half life period for the catalytic decom

1.	At a certain temperature, the half life period for the catalytic decomposition of ammonia were found to be a follows. Pressure (mm): 100 200 Half life (min.) : 1.92 1.0 What is the unit of rate constant?
Answer» t 1/2 ) 2 (t 1/2 ) 1 =( a 1 a 2 ) n−1 where, n is order of reactionFrom the given data,1.923.52 =( 666713333 ) n−1 (a∝ INITIAL PRESSURE) =(2) n−1 log 1.923.52 =(n−1)log2=0.3010×(n−1)0.2632=0.3010×(n−1)n=1.87≈2Similar calculations are made between first and THIRD observations, n comes equal to 1.908 (≈2).Thus, the REACTION is of second order.mark me as brainlist