1.

At a certain temperature, the half life period for the catalytic decomposition of ammonia was found as follows: Calculate order of the reaction.

Answer»

Solution :For the reaction of nth ORDER,
`(t_(1//2))_(1)/(t_(1//2))_(2)= {[A_(0)]_(2)/[A_(0)]_(1)}^(N-1)`
From the given data,
`(3.52)/(1.92) = (13333/6667)^(n-1) = (2)^(n-1)` `(a propto "initial PRESSURE")`
`LOG(3.52)/(1.92) = (n-1) log2, 0.2632 = (n-1) xx 0.3010`
`n-1 = 0.2632/0.3010 = 0.874, n =1.87 ~~2`
The reaction is of second order.


Discussion

No Comment Found

Related InterviewSolutions