1.

At a certain place the angle of dip is 30^@ and the horizontal component of earth's magnetic field is 3.2 xx 10^(-5)T. Earth's total magnetic field at the place is

Answer»

`(3.2)/(sqrt3) xx 10^(-5)`
`(6.4)/(SQRT(3)) xx 10^(-5) T `
`3.2 xx 10^(-5) T`
`6.4 xx 10^(-5) T`

Solution :`B_E = (B_H)/(cos delta) = (3.2xx10^(-15))/(cos 30^(@)`


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