1.

At 90^(@)C, pure water has [H_(3)O^(+)]=10^(-6)mol L^(-).The value of K_(w) at 90^(@)Cis:

Answer»

`1xx10^(-6)`
`1xx10^(-8)`
`1xx10^(-12)`
`1xx10^(-14)`

Solution :`K_(w)=[H_(3)O]^(+)[OH^(-)]=[H_(3)O^(+)]^(2)`
`=(10^(-6))^(2)=10^(-12)`.


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