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At 80∘ C, the vapour pressure of a pure liquid A is 520 mm Hg and that of a pure liquid of B is 1000 mm Hg. If the ideal mixture of liquids A and B boils at 80∘ C and 1 atm pressure, the amount of solution A in the mixture is: (1 atm = 760 mm Hg) |
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Answer» At 80∘ C, the vapour pressure of a pure liquid A is 520 mm Hg and that of a pure liquid of B is 1000 mm Hg. If the ideal mixture of liquids A and B boils at 80∘ C and 1 atm pressure, the amount of solution A in the mixture is: (1 atm = 760 mm Hg) |
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