1.

At 80^(@)C, distilled water has [H_(3)O^(+)] concentration equal to 1 xx 10^(-6) mole/litre. The value of K_(w) at this temperature will be

Answer»

`1 xx 10^(-6)`
`1 xx 10^(-9)`
`1 xx 10^(-12)`
`1 xx 10^(-15)`

SOLUTION :`K_(w) = [H_(3)O^(+)][OH^(-)]`
Concentration of `H_(3)O^(+)` in distilled WATER `= 1 xx 10^(-6)` mol/l.
Now `[H_(3)O^(+)] = [OH^(-)]`
`K_(w) = [1 xx 10^(-6)] xx [1 xx 10^(-6)] = 1 xx 10^(-12)`.


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