1.

At 550K, the K_(c) for the following reaction is 10^(4)mol^(-1)LX_((g))+Y_((g))hArrX_((g)). At eqilibrium, it was observed that [X]=1/2[Y]=1/2[Z]. What is value of [Z] (in mol L^(-1)) at equlibrium

Answer»

`2xx10^(-4)`
`10^(-4)`
`2xx10^(4)`
`10^(4)`

Solution :`K_(c)=([Z])/([X][Y])implies1/2[Y]=[X]=1/2[Z]=a(say)`
`therefore[Z]=2A,[Y]=2a,[X]=a`
`10^(4)=(2a)/(a.2a)impliesa=10^(-4)`
`[Z]=2a=2xx10^(-4)`


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