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At 518^(@)C, the rate of decomposition of a simple of gaseous acetaldehyde initially at a pressure of 363 to "rr" was 1 to "rr" s^(-1) when 5% had reacted and 0.5 to "rr" s^(-1) when 33% had reached.The order of reaction is:

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Solution :b) Assume that the order of reaction with RESPECT to gaseous acetaldehyde is x.
Ist CASE
Reaction rate (r ) = `k[363 " torr " xx 0.95]^(x)`
`k[344.85]^(x)`………..(i)
IIND case:
`0.5" torr "s^(-1) = k[363 " torr " xx 0.67]^(x)`
`=k[243.21]^(x)`............(ii)
Divide i) by ii),
`(1 " torr " s^(-1))/(0.5 " torr "s^(-1))= [344.85]/[243.21]`
or `(2)^(1) = (1.414)^(x)`
or `x=2`


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