1.

At 500 K, equilibrium constant, K_(c ), for the following reaction is 5.(1)/(2)H_(2)(g)+(1)/(2)I_(2)(g)hArr HI(g)What would be the equilibrium constant K_(c ) for the reaction 2HI(g)hArr H_(2)(g)+I_(2)(g)

Answer»

`0.04`
`0.4`
25
`2.5`

Solution :`(1)/(2)H_(2)(g)+(1)/(2)I_(1)(g)HARR HI(g)K_(a)=5`
`HI(g)hArr (1)/(2)H_(2)(g)+(1)/(2)I_(2)(g)K_(a)=(1)/(5)`
`2HI(g)hArr H_(2)(g)+I_(2)(g)K_(a)=((1)/(5))^(2)=0.04`


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