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At 500 K, 0.10 mole of PCl5 are heated in a 8.2 L flask. The pressure of equilibrium mixture is found to be 0.1 atm. Calculate Kp(in atm) for the reaction.PCl5(g)⇌PCl3(g)+Cl2(g)Given: R=0.082 L atm K−1 mol−1 |
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Answer» At 500 K, 0.10 mole of PCl5 are heated in a 8.2 L flask. The pressure of equilibrium mixture is found to be 0.1 atm. Calculate Kp(in atm) for the reaction. PCl5(g)⇌PCl3(g)+Cl2(g) Given: R=0.082 L atm K−1 mol−1 |
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