1.

At 490^(@)C, the equilibrium constant for the stnthesis of HI is 50, the value of K for the dissocisation of HI will be

Answer»

`20.0`
`2.0`
`0.2`
0.02`

Solution :K for DISSOCIATION of `HI=? H_(2)+I_(2)hArr2HI`
`K_(a)=50,K_(b)=1/50=0.02`


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