At 450 K, Kp=2.0×1010/bar for the given reaction at equilibrium. 2SO2 – InterviewSolution

1.	At 450 K, Kp=2.0×1010/bar for the given reaction at equilibrium. 2SO2(g)+O2(g)↔2SO3(g) What is Kc at this temperature?
Answer» At 450 K, $K_{p} = 2.0 \times 10^{10} / b a r$ for the given reaction at equilibrium. $2 S O_{2 (g)} + O_{2 (g)} \leftrightarrow 2 S O_{3 (g)}$ What is $K_{c}$ at this temperature?

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