1.

At 40^(@)C, the vapour pressure os water is 55.3 mmHg. Calculate the vapour pressure at the same temperature over 10% aqueous solution of urea [CO(NH_(2))_(2)].

Answer»


Solution :Mass of urea in 100 g of SOUTION = 10 = 90 g
`"Mass of WATER in the soltion"=100-10=90g`
`"No. of moles of urea"=((10g))/((60"g mol"^(-1)))=5.0 mol`
`"No. of moles of water" ((90g))/((18"g mol"^(-1)))=5.0 mol`
`"Mole fraction of water"=((5.0 mol))/((5.0mol)+(0.17 mol))=(5.0)/(5.17)=0.967`
`"Vapoure pressure of water over aquious solution "=P_("water")^(@)xxC_("water")=(55.3mm)xx0.967`
=53.48 MM Hg.


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