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At 300 K, two solutions of glucose in water of concnetration 0.01 M and 0.001 M are separted by semipermeable membrane with respect to water. On which solution, the pressure should be applied to prevent osmosis? Calculate the magnitude of this applied presssure. |
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Answer» SOLUTION :`pi=CRT` For 0.01 M solution, `pi_(1)=0.01xx0.821xx300="0.2463 atm"` For 0.001 M solution, `pi_(2)=0.001xx0.821 xx300="0.02463 atm"` As movement of solvent molecules occurs from DILUTE to CONCENTRATION solution, pressure should be applied on CONCENTRATED solution, i.e., on 0.01 M solution to prevent osmosis. Magnitude of external pressure `=0.2463-0.0246="0.2217 atm"` |
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