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At 300 K, 36 g of glucose present per litre of the solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bar at the same temperature, what wolud be its concentrain ? |
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Answer» `"Fro a solution," n_(B)"and T are all constants"` `thereforepi_(1)V_(1)=pi_(2)V_(2)orV_(2)=(pi_(1)V_(1))/(pi_(2))=((4.98"BAR")xx(1L))/((1.52"bar"))=3.28 L` `"No. of moles of solute"(n_(B))=(36g)//(180" g mol"^(-1))=0.2 mol` `"Molar concentration ( C) in second case"=n_(B)/V_(2)=((0.2 mol))/((3.28 L))=0.061" mol L"^(-1)=0.061 M` |
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