At `300 K`, `36 g` of glucose present per litre in its solution has an osmotic pressure of `4.98 bar`. If the osmotic pressure of the solution is `1.52 bar` at the same temperature, what would be its concentration?

At `300 K`, `36 g` of glucose present per litre in its solution has an

1.	At `300 K`, `36 g` of glucose present per litre in its solution has an osmotic pressure of `4.98 bar`. If the osmotic pressure of the solution is `1.52 bar` at the same temperature, what would be its concentration?
Answer» Correct Answer - `0.061M` First case `W_(2)=36g, P=4.98 ba r`, `Mw_(2)(` glucose `)=180,V=1L,` `P=(n)/(V)RT` `4.98=(36)/(180xx1)RT …..(i)` Second case `1.52=CRT ….(ii)` Dividing `Eq. (i)` by `Eq. (ii)`, we get `(4.98)/(1.52)=(0.2RT)/(CRT)` `C=(0.2xx1.52)/(4.98)=0.61M` The concentration of solution `=0.061M`

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At `300 K`, `36 g` of glucose present per litre in its solution has an osmotic pressure of `4.98 bar`. If the osmotic pressure of the solution is `1.52 bar` at the same temperature, what would be its concentration?

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