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At 300 K, 36 g of glucose present per litre in its solution has an osmotic pressure of 4.98 bar. If osmotic pressure of the solution is 1.52 bar at the same temperature, what would be its concentration?

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Solution :`pi_(1)=C_(1)RT,""pi_(2)=C_(2)RT""THEREFORE""pi_(1)//pi_(2)=C_(1)//C_(2)`
`"4.98bar = 1.52 bar"=(36//"180 mol L"^(-1))//C_(2)"or"C_(2)=0.061" mol L"^(-1) = 0.061xx180gL^(-1)=10.98gL^(-1)`


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