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At 30^(@)C, K_(p) for the dissociation reaction :SO_(2)Cl_(2)(g) hArr SO_(2)(g)+Cl_(2)(g)is 2.9xx10^(-2) atm. If the total pressure is1 atm, the degree of dissociation of SO_(2)Cl_(2) is : (assume 1-alpha^(2)=1). |
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Answer» `87%` If degree of DISSOCIATION is `alpha` `1-alpha "" alpha "" alpha` Total no. of MOLES `=1-alpha+alpha+alpha=1+alpha` `pSO_(2)=(alpha P)/(1+alpha)=(alpha)/(1+alpha)` `pCl_(2)=(alpha P)/(1+alpha)=(alpha)/(1+alpha)` `pSO_(2)Cl_(2)=(1-alpha)/(1+alpha)P=(1-alpha)/(1+alpha)` `K_(p)=((pSO_(2))xx(pCl_(2)))/(p(SO_(2)Cl_(2)))` `=(((alpha)/(1+alpha))((alpha)/(1+alpha)))/((1-alpha)/(1+alpha))` `K_(p)=(alpha^(2))/(1-alpha^(2))=alpha^(2)` `therefore alpha^(2)=K_(p)=2.9xx10^(-2)` `= sqrt(2.9xx10^(-12))=0.17=17%` |
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