1.

At 298 K, the solubility product of MI is 10^(-6) (conc. Are expressed as mol kg^(-1)). The solubility of MI in 0.1 molal KI solution is :

Answer»

`10^(-6)mol kg^(-1)`
`10^(-5)mol kg^(-1)`
`10^(-4)mol kg^(-1)`
`10^(-3)mol kg^(-1)`

ANSWER :B


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