1.

At 298 K temperature the activation energy for the reaction X_(2)+Y_(2)toXY+20KJ is 15 KJ. What will be the activation energy for the reaction 2XYto X_(2)+Y_(2)?

Answer»

`+35KJ`
`-35KJ`
`-5KJ`
`-15KJ`

SOLUTION :`Delta_(R)H=("Activation energy of FORWARD REACTION")-("Activation energy of reverse reaction")`
`therefore` -20=15 -x
`therefore` x=35 KJ


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