1.

At 298 K temperature, how much pressure of H_(2) is required to make hydrogen electrode potential of pure water be zero ?

Answer»

`10^(-12)` atm
`10^(-10)` atm
`10^(-4)` atm
`10^(-14)` atm

Solution :`E=E^(@)-(0.0591)/(2)"log"(p_(H_(2)))/([H^(+)]^(2))`
`=0-(0.0591)/(2)"log"(p_(H_(2)))/((10^(-7))^(2))`
So, if `p_(H_(2))=10^(-14)` then POTENTIAL of hyddrogen ELECTRODE will be 0.


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