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At 298 K, `1000 cm^(3)` of a solution cocontaining 4.34 g solute shows osmotic pressure of 2.55 atm. What is the molar mass of solute ? `(R=0.0821Latm K_(-1)mol^(-1))`A. `41.64 g mol^(-1)`B. `82.73 g mol^(-1)`C. `58.31 g mol^(-1)`D. `91.65 g mol^(-1)` |
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Answer» Correct Answer - A `pi=CRT=(w)/(Mw)xx(1000)/(v(mL))xxRxxT` `2.55=(4.34)/(Mw)xx(1000)/(1000)xx0.082xx298` `M_(w)=41.64` |
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