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At 27^(@)C temperature time required for 75 % completion of a first order reaction 20 seconds.What will be its rate constatn?

Answer»

0.693 `s^(-1) mol^(-1)` LT
0.0693 `s^(-1)`
0.693 `s^(-1)`
0.0693 `s^(-1) mol^(-1)` lt

Solution :For =`(1)/(t)` in `(CO)/(ct)` at 75% completion :Ct =25%
`K=(2.303)/(20)` log `(100)/(25)=0.0697 sec^(-1)`


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