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At 27^(@)C temperature, 36 gm glucose is in 1 litre aqueous solution has pi = 4.98 bar. Find out concentration if pi = 1.52 bar at same temperature. |
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Answer» Solution :`pi = iCRT = CRT (because i=1" for GLUCOSE")` `4.98 =(36)/(180)xx RT ""` ….(1) `pi = C xx RT ""` …..(2) Now,`("equation (1)")/("equation (2)")=(4.98)/(pi)=(36)/(180)xx(1)/(C )` `therefore C = 0.061 MOL L^(-1)` |
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