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At `25^(@)C`, the solubility product of `Hg_(2)Cl_(2)` in water is `3.2 xx 10^(-17) mol^(3) dm^(-9)`. What is the solubility of `Hg_(2)Cl_(2)` in water `25^(@)C`A. `1.2 xx 10^(-12)M`B. `3.0 xx 10^(-6) M`C. `2 xx 10^(-6) M`D. `1.2 xx 10^(-16) M` |
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Answer» Correct Answer - C Here `Hg_(2)Cl_(2) rarr Hg_(2)^(2+) + 2Cl^(-)` Let the concentration of `Hg_(2)^(2+)` be = x Now, for each `Hg_(2)^(2+)` ion, two `Cl^(-)` ions are produced `:.` Concentration of `Cl^(-)` ions = 2x `K_(sp) = [Hg_(2)^(2+)][Cl^(-)]^(2)` `x(2x)^(2) = 3.2 xx 10^(-17) rArr 4x^(3) = 32 xx 10^(-18)` `rArr x^(3) = (32)/(4) xx 10^(-18) :. x = 2 xx 10^(-6) M` |
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