1.

At 25^(@)C, the solubility product of Hg_(2)Cl_(2) in water is 3.2 xx 10^(-17) mol^(3) dm^(-9). What is the solubility of Hg_(2)Cl_(2) in water 25^(@)C

Answer»

`1.2 XX 10^(-12)M`
`3.0 xx 10^(-6) M`
`2 xx 10^(-6) M`
`1.2 xx 10^(-16) M`

Solution :Here `Hg_(2)Cl_(2) rarr Hg_(2)^(2+) + 2Cl^(-)`
Let the concentration of `Hg_(2)^(2+)` be = x
Now, for each `Hg_(2)^(2+)` ion, two `Cl^(-)` ions are produced
`:.` Concentration of `Cl^(-)` ions = 2X
`K_(sp) = [Hg_(2)^(2+)][Cl^(-)]^(2)`
`x(2x)^(2) = 3.2 xx 10^(-17)rArr 4x^(3) = 32 xx 10^(-18)`
`rArr x^(3) = (32)/(4) xx 10^(-18) :. x = 2 xx 10^(-6) M`


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