1.

At 25^@ C, the solubility product of a salt of MX_2 type is 3.2 xx10^(-8) in water. The solubility (in mol/L) of MX_2 in water at the same temperature will be

Answer»

`1.2 XX 10^(-3)`
`2 xx 10^(-3) `
`3.2xx 10^(-3)`
`1.75 xx 10^(-3)`

Solution :`{:(MX_2 hArr ,M^+, 2X^(-)),(,S,2S):}`
` K_(sp )= S xx (2s)^2 =4S^3`
` 4S^3 = 3.2 xx 10^(-8)`
` S= SQRT((3.2 xx 10^(-8))/(4))`
` S= 2 xx 10^(-3)`


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