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At 25^(@)C temperature, if for given unknown half cell has 0.34 Volt potential, then calculate standard reduction potential for copper : Pt|H_(2(g))(1" atm")|H_((1M))^(+)||Cu_((1M))^(2+)|Cu |
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Answer» `-0.34` Volt Oxidation : `H_(2(g)) to 2H_((aq))^(+)+2e^(-) , E_(RED)^(@)=`zero REDUCTION : `Cu_((aq))^(2+)+2e^(-) to Cu_((S)),""E_(red)^(@)=(?)` `E_(cell)^(@)=E_(red)^(@)("CATHODE")-E_(red)^(@)("ANODE")` `therefore 0.34=E_(Cu^(2+)//Cu)^(@)-E_(H^(+)//H_(2))^(@)` `therefore 0.34V=E_(Cu^(2+)//Cu)^(@)-0.0` `therefore E_(Cu^(2+)//Cu)^(@)=+0.34V`. |
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