1.

At 25^(@)C specific coductivity of a normal solution of KCl is 0.002765 mho. The resistance of cell is 400 ohms. The cell constant is:-

Answer»

0.815
1.016
1.106
2.016

Solution :Cell constant`=("SPECIFIC CONDUCTIVITY")/("OBSERVED CONDUCTANCE")`
`=(0.002765)/(1//R)=0.002765xx400=1.106`


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