At `25^(@)`C, `K_(sp)` for `PbBr_(2)` is equal to `8xx10^(-5)`. If the salt is `80%` dissociated, What is the solubility of `PbBr_(2)` in mol//litre?A. `[(10^(-4))/(1.6 xx 1.6)]^(1//3)`B. `[(10^(-5))/(1.6 xx 1.6)]^(1//3)`C. `[(10^(-4))/(0.8 xx 0.8)]^(1//3)`D. `[(10^(-3))/(1.6 xx 1.6)]^(1//2)`

At `25^(@)`C, `K_(sp)` for `PbBr_(2)` is equal to `8xx10^(-5)`. If the

1.	At `25^(@)`C, `K_(sp)` for `PbBr_(2)` is equal to `8xx10^(-5)`. If the salt is `80%` dissociated, What is the solubility of `PbBr_(2)` in mol//litre?A. `[(10^(-4))/(1.6 xx 1.6)]^(1//3)`B. `[(10^(-5))/(1.6 xx 1.6)]^(1//3)`C. `[(10^(-4))/(0.8 xx 0.8)]^(1//3)`D. `[(10^(-3))/(1.6 xx 1.6)]^(1//2)`
Answer» Correct Answer - A `PbBr_(2(s)) hArr underset(0.8(s))(Pb_((aq))^(+2))+ underset(2 xx 0.8(s))(2Br_((aq))^(-))`

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At `25^(@)`C, `K_(sp)` for `PbBr_(2)` is equal to `8xx10^(-5)`. If the salt is `80%` dissociated, What is the solubility of `PbBr_(2)` in mol//litre?A. `[(10^(-4))/(1.6 xx 1.6)]^(1//3)`B. `[(10^(-5))/(1.6 xx 1.6)]^(1//3)`C. `[(10^(-4))/(0.8 xx 0.8)]^(1//3)`D. `[(10^(-3))/(1.6 xx 1.6)]^(1//2)`

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