1.

At 25^(@)C aqueous solution of glucose (molecular weight = 180 g mol^(-1)) is isotonic with a 2% aqueous solution containing an unknown solute. What is the molecular weight of the unknown solute

Answer»

60
80
72
63

Solution :`pi_("GLUCOSE")=pi_("UNKNOWN SOLUTE")`
`therefore (m_(1))/(M_(1))=(m_(2))/(M_(2))` or `(5)/(180)=(2)/(M_(2))rArr M_(2)=72`.


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