1.

At 25^(@)C, a 0.1m solution of CH_(3)COOH is 1.35% dissociated. Calculate the freezing point and osmotic pressure of the solution. Compare your results with those expected under conditions of no dissociation . K_(f) for water =1.86^(@)Cm^(-1).

Answer»


Solution :`(DeltaT_(F))_("normal")=K_(f)xxm`…………(Eqn 7)
`=1.86xx0.2`
`=0.372`
We have `i=("OBSERVED colligative property")/("normal colligative property")`………..(Eqn 9)
`=(0.68)/(0.372)=1.83`
Again, `i=("observed osmotic pressure")/("normal osmatic pressure")`
`:.` observed osmotic pressure `=i xx` normal osmotic pressure
`=i xx cRT`............(Eqn 6)
`=1.83xx0.2xx0.082xx273`
`=8.2` atm


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