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At 20^(@)C, the Ag^(+) ion concentation in a saturated solution of Ag_(2)CrO_(4) is 1.5 xx 10^(-4) mole/litre. At 20^(@)C, the solubility product of Ag_(2)CrO_(4) would be |
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Answer» `3.3750 xx 10^(-12)` `K_(sp) = 4S^(3)` given `2S = 1.5 xx 10^(-4)` `:. K_(sp) = (2S)^(2) xx S` `= (1.5 xx 10^(-4))^(2) xx ((1.5 xx 10^(-4))/(2)) = 1.6875 xx 10^(-12)` |
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