1.

At `1600K` maximum radiation is emitted at a wavelength of `2mu_(M)`. Then what will be corresponding wavelength at `2000K` ?

Answer» Using `lambda_(m_(1))T_(1)=lambda_(m_(2))T_(2)`
`:. Lambda_(m_(2))=(lambda_(m_(1))T_(1))/(T_(2))`
`:. Lambda_(m_(2))=(2xx10^(-6)xx1600)/(2000)`
`implies lambda_(m_(2))=1.6mu m`


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