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At `1600K` maximum radiation is emitted at a wavelength of `2mu_(M)`. Then what will be corresponding wavelength at `2000K` ? |
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Answer» Using `lambda_(m_(1))T_(1)=lambda_(m_(2))T_(2)` `:. Lambda_(m_(2))=(lambda_(m_(1))T_(1))/(T_(2))` `:. Lambda_(m_(2))=(2xx10^(-6)xx1600)/(2000)` `implies lambda_(m_(2))=1.6mu m` |
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