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At 1323°C the equilibrium constant for the reaction :Br2(g) ------> 2Br(g); Kc=10^(-3)A 0.2L vessel containing an equilibrium mixture of gases has 0.24g Br2(g) in it. What is the mass of Br(g)in the vessel? |
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Answer» MOLES Br2 = 0.245 g/ 159.808 g/mol=0.00153 [Br2]= 0.00153 / 0.190 L=0.00807 M 1.04 x 10^-3 = [BR]^2/ [Br2] = [Br]^2 / 0.00807 [Br]= 8.93 x 10^-6 M moles Br = 8.93 x 10^-6 x 0.190=1.59 x 10^-6 mass Br = 1.59 x 10^-6 x 79.904 g/mol=0.000127 g |
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