1.

At 1127 K and 1 atm pressure, a gaseous mixture of CO and CO₂ in equilibrium with solid carbon has 90.55% CO by mass, , Calculate Kc for this reaction at the above temperature.

Answer»

consider the weight of mixture is 100 g,In that, 90.55% CO by mass MEANS 90.55 g of CO and 9.45 g of CO2 present in the mixture. [ molar mass of CO = 28 g/mol ]   [ molar mass of ]  PARTIAL pressure of CO = MOLE fraction of CO  total pressure  = 0.938   1 atm  Partial pressure of CO = 0.938 atmSimilarly, partial pressure of = 0.062 × 1 atmPartial pressure of = 0.062 atm  Then, ∆ng = NUMBER of mole of gaseous PRODUCTS - number of mole of gaseous reactants  = 2 - 1 = 1



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