1.

At 1090K, K_(p) for the reaction CO_(2)(g) +C(s) rarr 2CO(g) is 10 atm, At the constant temperature ,Equilibrium position will shift, when pressure change occurs. In the above reaction, at what total pressure will the gaes analyse 8% CO_(2) by volume ?

Answer»

<P>10 ATM
0.23 atm
0.95 atm
0.45 atm

Solution :GIVEN`%` of `CO_(2) = 8, % CO = 92 `
`k_(p) = ((P_(CO))^(2))/((P_(CO_(2)))) = ( ( 0.92P)^(2))/( 0.08) = ( ( 0.92 )^(2) P )/(0.08) = 10`
`P = ( 10 xx 10.08)/( ( 0.92)^(2)) = 0.95 ` atm


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