1.

At 1000 k , the pressure of iodine gasis found to be 0.112 atm due to partial dissociation of I_2 (g) into I. Had there been no dissociation , the pressure would have been 0.074 atm. Calculate the value of K_p for the reaction, I_2 (g) hArr 2I(g)

Answer»

SOLUTION :`K_p =0.16 ATM`


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