1.

At 100^(@)C the vapour pressure of a solution of 6.5 gm of a solute in 100 g water is 732 mm. If K_(b)=0.52, the boiling point of this solution will be :

Answer»

`100^(@)C`
`102^(@)C`
`103^(@)C`
`101^(@)C`

Solution :`(P_(1)^(0)-P_(1))/(P_(1)^(0))=(n_(2))/(n_(1))`
`(760-732)/(760)=(6.5xx18)/(M_(2)xx100) "" therefore M_(2)=31.6`
`Delta T_(b)=(0.52xx6.5xx1000)/(31.6xx100)=1.07`
`therefore` Vapour PRESSURE `= 100+1.07`
`= 101.07^(@)C`
`~~101^(@)C`


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